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                  Tuesday, February 18th 2020, 6:56 pm
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            <p>2.给出四个[年,月],判断此月有多少天.题目给出了闰年判断方法的伪代码.</p>
<pre><code class="cpp">#include&lt;iostream&gt;

using namespace std;

int months[2][13]={
    {0,31,28,31,30,31,30,31,31,30,31,30,31},//平年
    {0,31,29,31,30,31,30,31,31,30,31,30,31}//闰年
};

bool isrein(int year){
    return (year%400==0)||(year%4==0&amp;&amp;year%100!=0);
}

int main(){
    int year,month;
    while(cin&gt;&gt;year&gt;&gt;month){
        if(isrein(year)) cout&lt;&lt;months[1][month];
        else cout&lt;&lt;months[0][month];
    }
}
</code></pre>
<p>3.给出一些标识符,判断合法标识符有多少个.(与 C语言中标识符定义一致.)</p>
<pre><code class="cpp">#include&lt;iostream&gt;
#include&lt;cstring&gt;
#include&lt;vector&gt;
using namespace std;

bool first(char c){
    return (c&gt;=&#39;a&#39;&amp;&amp;c&lt;=&#39;z&#39;)||(c&gt;=&#39;A&#39;&amp;&amp;c&lt;=&#39;Z&#39;)||(c==&#39;_&#39;);
}

bool others(char c){
    return (c&gt;=&#39;a&#39;&amp;&amp;c&lt;=&#39;z&#39;)||(c&gt;=&#39;A&#39;&amp;&amp;c&lt;=&#39;Z&#39;)||isdigit(c)||(c==&#39;_&#39;);
}

int main(){
    int n;
    while(cin&gt;&gt;n){
        vector&lt;string&gt; v;
        int Count=0;
        for(int i=0;i&lt;n;i++){
            string s;
            cin&gt;&gt;s;
            v.push_back(s);
        }
        for(int i=0;i&lt;v.size();i++){
            string s1=v[i];
            if(first(s1[0])){
                bool flag=true;
                for(int j=1;j&lt;s1.size();j++){
                    if(!others(s1[j])) flag=false;
                }
                if(flag) Count++;
            }
            else continue;
        }
        cout&lt;&lt;Count&lt;&lt;endl;
    }
}
</code></pre>
<p>4.第四道,给出无向图连接矩阵,求各个连通分量</p>
<pre><code class="cpp">#include&lt;iostream&gt;
#include&lt;vector&gt;
#include&lt;cstdio&gt;
const int MAXN=1000;

int father[MAXN];
int height[MAXN];//以该节点为根的树的高度
using namespace std;

void Initial(){
    for(int i=0;i&lt;MAXN;i++){
        father[i]=i;
        height[i]=0;
        //inDegree[i]=0;
        //visit[i]=false;
    }
}

int FindRoot(int x){
    if(father[x]!=x) father[x]=FindRoot(father[x]);//注意写法
    return father[x];
}

void Union(int x,int y){
    x=FindRoot(x);
    y=FindRoot(y);
    if(x!=y){
        if(height[x]&lt;height[y]) father[x]=y;
        else if(height[x]&gt;height[y]) father[y]=x;//前面两种情况树高并没有变
        else{
            father[y]=x;
            height[x]++;
        }
    }
    return ;
}

int main(){
    FILE *fp1,*fp2;//1.定义指针
    fp1=fopen(&quot;in.txt&quot;,&quot;r&quot;);//2.指向文件
    fp2=fopen(&quot;out.txt&quot;,&quot;w&quot;);
    int n;
    fscanf(fp1,&quot;%d&quot;,&amp;n);//3.进行读写
    Initial();
    while(!feof(fp1)){
        int a,b;
        fscanf(fp1,&quot;%d&quot;,&amp;a);
        fscanf(fp1,&quot;%d&quot;,&amp;b);
        Union(a,b);
    }
    vector&lt;int&gt; roots;
    for(int i=1;i&lt;=n;i++){//因为序号是从1开始
        if(FindRoot(i)==i){
            roots.push_back(i);
        }
    }
}
</code></pre>
<p>5.给出一个整数分解成尽可能多的连续整数的和</p>
<pre><code class="cpp">#include&lt;iostream&gt;

using namespace std;

int main(){
    int n;
    while(cin&gt;&gt;n){
        int maxi=0,maxj=0;
        bool flag=false;
        for(int i=1;i&lt;=n/2;i++){
            int sum=0;
            for(int j=2;j&lt;n;j++){//j表示从i开始往后连续的长度
                sum=(i+i+j-1)*j/2;
                if(sum&gt;n) break;
                else if(sum==n){
                    flag=true;
                    if(j&gt;maxj){
                        maxi=i;
                        maxj=j;
                    }
                }
            }
        }
        if(flag){
            for(int i=maxi;maxj&gt;0;maxj--,i++){
                cout&lt;&lt;i&lt;&lt;&quot; &quot;;
            }
            cout&lt;&lt;endl;
        }
        else cout&lt;&lt;&quot;分解失败&quot;&lt;&lt;endl;
    }
}
</code></pre>
<p>6.给出带括号的四则运算表达式,要求给出逆波兰式</p>
<pre><code class="cpp">#include&lt;iostream&gt;
#include&lt;cstdio&gt;
#include&lt;cctype&gt;
#include&lt;cstring&gt;
#include&lt;stack&gt;

using namespace std;

stack&lt;char&gt; Stack;
char output[500];
int outLen;
int Priority(char c){//判断运算符优先级
    if(c==&#39;*&#39;||c==&#39;/&#39;) return 2;
    else if(c==&#39;+&#39;||c==&#39;-&#39;) return 1;
    else return 0;//&#39;(&#39;
}

bool isOperator(char op)                //判断是不是操作符
{
    return (op==&#39;+&#39; || op==&#39;-&#39; || op==&#39;*&#39; || op==&#39;/&#39;);
}

void rePolish(string s,int len){//输出逆波兰式
    memset(output,&#39;\0&#39;,sizeof(output));
    outLen=0;
    for(int i=0;i&lt;len;++i){
        //操作数
        if(isdigit(s[i])){
            cout&lt;&lt;&quot;shu:&quot;&lt;&lt;s[i]&lt;&lt;endl;
            output[outLen++] = s[i];
            while (i+1&lt;len&amp;&amp;isdigit(s[i+1])){
                output[outLen++] = s[i+1];
                ++i;
            }
            output[outLen++] = &#39; &#39;;        //空格隔开
        }
        //运算符
        else if (isOperator(s[i])){
            cout&lt;&lt;&quot;fu:&quot;&lt;&lt;s[i]&lt;&lt;endl;
            if(!Stack.empty()&amp;&amp;Priority(Stack.top())&gt;=Priority(s[i])){
                while(Priority(Stack.top())&gt;=Priority(s[i])){
                    output[outLen++]=Stack.top();
                    output[outLen++] = &#39; &#39;;
                    Stack.pop();
                }
            }
            else Stack.push(s[i]);//栈为空，或者栈顶优先级更小
        }
        //&#39;(&#39;
        else if (s[i]==&#39;(&#39;){
            cout&lt;&lt;&quot;(:&quot;&lt;&lt;s[i]&lt;&lt;endl;
            Stack.push(s[i]);
        }
        //&#39;)&#39;
        else if (s[i]==&#39;)&#39;){
            cout&lt;&lt;&quot;):&quot;&lt;&lt;s[i]&lt;&lt;endl;
            while (Stack.top()!=&#39;(&#39;){
                output[outLen++] = Stack.top();
                output[outLen++] = &#39; &#39;;
                Stack.pop();
            }
            Stack.pop();// 此时Stack.top()=&#39;(&#39;,跳过)
        }
        else continue;
    }
    while (!Stack.empty()){//输入完毕，栈中剩余的所有操作符出栈
        output[outLen++] = Stack.top();
        output[outLen++] = &#39; &#39;;
        Stack.pop();
    }
}

int main(){
    string s;
    while (getline(cin,s)){
        cout&lt;&lt;s&lt;&lt;&quot; &quot;&lt;&lt;s.size();
        Stack.push(&#39;#&#39;);
        rePolish(s,s.size());
        output[outLen-1] = &#39;\0&#39;;
        printf(&quot;%s\n&quot;,output);
    }
    return 0;
}
</code></pre>

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          //下标等于原来下标+1  余 词语总数
          a_idx = (a_idx + 1) % a.length;
          //获取鼠标指针的位置，分别相对于文档的左和右边缘。
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          //在鼠标的指针的位置给$i定义的span标签添加css样式
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          //animate() 方法执行 CSS 属性集的自定义动画。
          //该方法通过CSS样式将元素从一个状态改变为另一个状态。CSS属性值是逐渐改变的，这样就可以创建动画效果。
          //详情请看http://www.w3school.com.cn/jquery/effect_animate.asp
          $i.animate({
            //将原来的位置向上移动180
            "top": y - 180,
            "opacity": 0
            //1500动画的速度
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            //时间到了自动删除
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          });
        });
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